(3y^4/x^2)/(9/16x^5y^12)

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Solution for (3y^4/x^2)/(9/16x^5y^12) equation: 


D( x )

(9/16)*x^5*y^12 = 0

x^2 = 0

(9/16)*x^5*y^12 = 0

(9/16)*x^5*y^12 = 0

9/16*x^5*y^12 = 0 // : 9/16*y^12

x^5 = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

((3*y^4)/(x^2))/((9/16)*x^5*y^12) = 0

16/3*x^-7*y^-8 = 0 // : 16/3*y^-8

x^-7 = 0

x naleu017Cy do O

x belongs to the empty set

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